610A - Pasha and Stick - CodeForces Solution


combinatorics math *1000

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Python Code:

n=int(input())
if n%2:print(0)
else:
	d=n//2
	if d%2:print(d//2)
	else:print(d//2-1)

C++ Code:

#include<bits/stdc++.h>
using namespace std;
int main()
{
    long long int n;
    cin>>n;
    if(n%2!=0){
        cout<<0;
        return 0;
    }
    if(n%2==0){
        int a=n/2;
        if(a%2==0){
            a=(a/2)-1;
        }
        else{
            a=a/2;
        }
        cout<<a;
    }
    return 0;
}


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